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Subject: | [CBQ] Railroad Freight Cars Moving on Their Own |
From: | "Bob Weber" <eng95@comcast.net> |
Date: | Mon, 16 Nov 2009 05:19:47 -0800 |
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I tried using this Davis formula for Railway Rolling Resistance, R(rolling resistance) = (1.3wn+29n) + bwnV + CAV² and from that computed the deceleration to get time and distance until it stops. The accuracy of the results depends on the real rolling resistance and drag coefficients. I used the following parameters in the equation and solved for the resistance in 10 second steps to get my answer. Initial speed=50 mph, rolling res=0.045, drag=0.025, weight of car=30 tons and front area of car=90 ft² My spread sheet gives car travel 2.4 miles and takes 7.5 minutes to come to a stop. Bob [Non-text portions of this message have been removed] ------------------------------------ Yahoo! Groups Links <*> To visit your group on the web, go to: http://groups.yahoo.com/group/CBQ/ <*> Your email settings: Individual Email | Traditional <*> To change settings online go to: http://groups.yahoo.com/group/CBQ/join (Yahoo! ID required) <*> To change settings via email: CBQ-digest@yahoogroups.com CBQ-fullfeatured@yahoogroups.com <*> To unsubscribe from this group, send an email to: CBQ-unsubscribe@yahoogroups.com <*> Your use of Yahoo! Groups is subject to: http://docs.yahoo.com/info/terms/ |
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